Given that the motor efficiency is 90%, we can calculate the power output: If the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 90 percent, determine the mechanical efficiency of the pump. Web an oil pump is drawing 44 kw of electric power while pumping oil with p= 860 kg/m3 at a rate of 0.1 m3/s. Volume flow rate, v = 0.1 m³/s. Power output of motor = (motor efficiency) × (power input) power output of motor = 0.96 × 44 kw power output of motor = 42.24 kw now, we need to find the power required to pump the oil.

Outlet diameter, d₂ = 12 cm. If the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 90 percent, determine the mechanical efficiency of the pump. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Web for the shaft power of the pump we have the following equation:

If the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 90 percent, determine the mechanical efficiency of the pump. Pressure rise, p = 500kpa. The electric power (p electric) supplied to the pump motor is given as 44 kw.

Web an oil pump is drawing 44 kw of electric power while pumping oil with p = 860 kg/m^3 at a rate of 0.1 m^3/s. Pressure rise, p = 500kpa. An oil pump is drawing 44 kw of electric power while pumping oil with ï =860 kg/mâ³ at a rate of 0.1 mâ³/s. Web an oil pump is drawing 44 kw of electric power while pumping oil with \rho ρ = 860 kg/m^3 at a rate of 0.1 m^3/s. An oil pump is drawing 44 kw of electric power while pumping oil with p= 860 kg/m3 at a rate of 0.1 m3/s.

Output power = motor efficiency x input power. We can convert this percentage to a decimal: The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively.

The Inlet And Outlet Diameters Of The Pipe Are 8 Cm And 12 Cm, Respectively.

If the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 90 percent, determine the mechanical efficiency of the pump. Web the power output of the pump can be calculated using the formula: P_output = p_input * η_motor where p_input is the power input to the pump and η_motor is the motor efficiency. Web an oil pump is drawing 44 kw of electric power while pumping oil with rho = 860 kg/m^3 at a rate of 0.07 m^3/s.

Web An Oil Pump Is Drawing 44 Kw Of Electric Power While Pumping Oil With Ρ = 860 Kg/M 3 At A Rate Of 0.1 M 3 /S.

Web if the pressure rise of oil in the pump is measured to be 500 kpa and the motor efficiency is 90 percent, determine the mechanical efficiency of the pump. We can convert this percentage to a decimal: We have given that an oil pump is drawing 44 kw of electric power. The mechanical efficiency of the pump is 91.8 % explanation:

Web An Oil Pump Is Drawing 44 Kw Of Electric Power While Pumping Oil With P= 860 Kg/M3 At A Rate Of 0.1 M3/S.

The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Web an oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m 3 at a rate of 0.1 m 3 /s. The mechanical efficiency for an oil pump is being determined. Web mechanical engineering questions and answers.

Web An Oil Pump Is Drawing 44 Kw Of Electric Power While Pumping Oil With R = 860 Kg/M3 At A Rate Of 0.1 M3/S.

The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. Web chemical engineering questions and answers. An oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m3 at a rate of 0.1 m3 /s. The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively.

The inlet and outlet diameters of the pipe are 8 cm and 12 cm, respectively. The efficiency of the motor () = 90% P_output = p_input * η_motor where p_input is the power input to the pump and η_motor is the motor efficiency. Web an oil pump is drawing 44 kw of electric power while pumping oil with p= 860 kg/m3 at a rate of 0.1 m3/s. Web an oil pump is drawing 44 kw of electric power while pumping oil with ρ = 860 kg/m 3 at a rate of 0.1 m 3 /s.